find the angle between vector u=i+sqrt 7 j and vector v=-i-4j to the nearest degree. a. 173 degreesb. 145 degreesc. 115 degreesd. 97 degrees

hence angle between vectors is option a ,173 degreeWhat is Vector Equation?When an equation has both direction as well as magnitude it refers to vector equation.How to calculate angle between two vectors?Formula used [tex]\alpha =cos^{-1} (\frac{u.v}{|u||v|})[/tex]u.v=1*(-1)+[tex]\sqrt{7} *(-4)[/tex]|u|=[tex]\sqrt{ 1^{2} +\sqrt{7} ^{2}}[/tex]=[tex]2\sqrt{2}[/tex]|v|=[tex]\sqrt{ (-1^{2}) +(-4^{2})[/tex]=[tex]\sqrt{17}[/tex][tex]\alpha =cos^{-1} (\frac{-1-4\sqrt{7} }{|2\sqrt{2} ||\sqrt{17} |})[/tex][tex]\alpha =cos^{-1} (\frac{-1-10.58}{2.82*4.12})[/tex][tex]\alpha =cos^{-1} (\frac{-11.58}{11.61})[/tex][tex]\alpha =cos^{-1} (-0.99)[/tex]hence option a 173 degree is correctLearn more about vectors