Vince uses a coordinate plane to map an amusement park. The ordered pairs are locations of entrances to different rides at the park. He graphs and labels the ordered pairs. Then he connects the points to show the path around the park. What is the length of the path on the grid?Please Help!

Answer:The length is 52 unitsStep-by-step explanation:we know thatThe length of the path. is equal to the perimeter of polygon A.B.C.D.E.F[tex]P=A.B+B.C+C.D+D.E+E.F+A.F[/tex]The formula to calculate the distance between two points is equal to [tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]step 1Find the distance A.Bwe have[tex]A(-7,7),B(6,7)[/tex]substitute in the formula[tex]d=\sqrt{(7-7)^{2}+(6+7)^{2}}[/tex][tex]d=\sqrt{(0)^{2}+(13)^{2}}[/tex][tex]d_A_B=13\ units[/tex]step 2Find the distance B.Cwe have[tex]B(6,7),C(6,-2)[/tex]substitute in the formula[tex]d=\sqrt{(-2-7)^{2}+(6-6)^{2}}[/tex][tex]d=\sqrt{(-9)^{2}+(0)^{2}}[/tex][tex]d_B_C=9\ units[/tex]step 3Find the distance C.Dwe have[tex]C(6,-2),D(3,-2)[/tex]substitute in the formula[tex]d=\sqrt{(-2+2)^{2}+(3-6)^{2}}[/tex][tex]d=\sqrt{(0)^{2}+(-3)^{2}}[/tex][tex]d_C_D=3\ units[/tex]step 4Find the distance D.Ewe have[tex]D(3,-2),E(3,-6)[/tex]substitute in the formula[tex]d=\sqrt{(-6+2)^{2}+(3-3)^{2}}[/tex][tex]d=\sqrt{(-4)^{2}+(0)^{2}}[/tex][tex]d_D_E=4\ units[/tex]step 5Find the distance E.Fwe have[tex]E(3,-6),F(-7,-6)[/tex]substitute in the formula[tex]d=\sqrt{(-6+6)^{2}+(-7-3)^{2}}[/tex][tex]d=\sqrt{(0)^{2}+(-10)^{2}}[/tex][tex]d_E_F=10\ units[/tex]step 6Find the distance A.Fwe have[tex]A(-7,7),F(-7,-6)[/tex]substitute in the formula[tex]d=\sqrt{(-6-7)^{2}+(-7+7)^{2}}[/tex][tex]d=\sqrt{(-13)^{2}+(0)^{2}}[/tex][tex]d_A_F=13\ units[/tex]step 7Find the perimeter[tex]P=A.B+B.C+C.D+D.E+E.F+A.F[/tex]substitute the values[tex]P=13+9+3+4+10+13[/tex][tex]P=52\ units[/tex]