The figure below is a net for a triangular prism. Side a = 45 inches, side b = 14 inches, side c = 30 inches, and altitude d = 20 inches. What is the surface area of this figure? A. 2,370 square inches B. 1,950 square inches C. 3,000 square inches D. 2,790 square inches

Answer:the answer is A.  2370 sq. inStep-by-step explanation:area of the triangles firstA = 1/2 ada = (45 in) (20 in)a = 1/2 (900 sq in)a = 450 sq in***remember to multiply 450 * 2 because you have 2 triangles***Total area of both triangles is 900 sq. in.Find the area of the 3 rectangles A = LW1st rectangle and 2nd rectanglea = cba = (30 in) (14 in)a = 420 sq in. (make sure you add this again in the Total Surface area)3rd rectanglea = aba = (45 in) (14 in)a = 630 sq. inTotal Surface area = 2 (1/2 ad) + 2(cb) + (ab)= 2 (450 sq. in) + 2 (420 sq. in) + 630 sq. in= 900 sq. in + 840 sq. in + 630 sq. in= 2370 sq. in