Q:

Logarithm help needed

Accepted Solution

A:
Answer:The answer to your question is: log₇ ([tex]\frac{xy}{z}[/tex])Step-by-step explanation:                           log₇ x + log₇ y - log₇ zFirst he must use the product rule that says:                          log a x + log a y = log a xyThen, he must use the quotient rule that says                          log a x - log a y = log a ([tex]\frac{x}{y}[/tex]He did not use these rules that's why his answer is incorrect.The correct answer is:                         log₇ (xy) - log₇ z                        log₇ [tex]\frac{xy}{z}[/tex]